To solve the exercise you can use the slope formula:
[tex]\begin{gathered} m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \text{ Where m is the slope and} \\ (x_1,y_1)\text{ and }(x_2,y_2)\text{ are two points through which the line passes} \end{gathered}[/tex]
So, in this case, you have
[tex]\begin{gathered} (x_1,y_1)=(-1,2) \\ (x_2,y_2)=(3,3) \end{gathered}[/tex][tex]\begin{gathered} m=\frac{3-2}{3-(-1)} \\ m=\frac{1}{3+1} \\ m=\frac{1}{4} \end{gathered}[/tex]
Therefore, the slope of the line that contains the points (-1,2) and (3,3) is
[tex]\frac{1}{4}[/tex]
and the correct answer is option B.
