Explanation
Step 1
if two lines are parallel, then
[tex]\text{slope}_{_1}=slope_2[/tex]So, we have
[tex]y=\frac{-1}{3}x+2\rightarrow y\text{ = mx+b}[/tex]Hence,
[tex]\begin{gathered} \text{slope}1=\frac{-1}{3} \\ \text{sloep}1=\text{ slope2,then} \\ \text{slope}_2=\frac{-1}{3} \end{gathered}[/tex]Step 2
according to the question , we can create any line, so we can select any point,
let
P1(0,0) and slope=-1/3
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \text{replacing} \\ y-0=-\frac{1}{3}(x-0) \\ y=-\frac{1}{3}x \end{gathered}[/tex]