I have pressure of 65 kPa and starting temperature of 25°C. If I raise the temperature to 167°C, what is the new pressure? (Equation: K= 273 +°CO 90 KPaO 100 kPaO 96 kPaO 97 kPa

Respuesta :

Answer:

96kPa. Option C is correct

Explanations:

According to Gay Lussac's law, the pressure of a given mass of gas is directly proportional to the temperature provided that the volume is constant. Mathematically:

[tex]\begin{gathered} P\alpha T \\ P=kT \\ k=\frac{P_1}{T_1}=\frac{P_2}{T_2} \end{gathered}[/tex]

Substituting the given parameters to determine the new pressure P2

[tex]\begin{gathered} P_2=\frac{P_1T_2}{T_1} \\ P_2=\frac{65\times(167+273)}{(25+273)} \\ P_2=\frac{65\times440}{298} \\ P_2=\frac{28600}{298}=95.97kPa \\ P_2\approx96kPa \end{gathered}[/tex]

Therefore the new pressure is 96kPa