In order to find a vector multiplication by a scalar, we follow the rule:
[tex]u\ast(n_1,n_2)_\Rightarrow(un_{1,}un_2)[/tex]
then, if we apply it to the vector v, we need to find the dimensions of the vector, for that we subtract the initial point from the terminal point,
[tex](-8-8,10-4)\Rightarrow(-16,6)[/tex]
then, multiply by the scalar -1/2,
[tex]-\frac{1}{2}\ast(-16,6)\Rightarrow(8,-3)[/tex]
Answer:
[tex](8,-3)[/tex]
