The general standard equation for the circle centered at (h, k) with radius r is given to be:
[tex](x-h)^2+(y-k)^2=r^2_{}[/tex]From the question provided, we have the center to be (-4, -6) and a radius of 3. Therefore, we have:
[tex]\begin{gathered} (h,k)=(-4,-6) \\ r=3 \end{gathered}[/tex]Hence, the equation of the circle is given to be:
[tex]\begin{gathered} (x-\lbrack-4\rbrack)^2-(y-\lbrack-6\rbrack)^2=3^2 \\ \Rightarrow(x+4)^2-(y+6)^2=9 \end{gathered}[/tex]The correct option is the LAST OPTION.
