The answer is option C
The points graph must be a solution to the equation. Then, in graph C, we have three points:
(0 , -2, 0)
(-2, 0, 0)
(0, 0, 4)
Now let's try each in the equation:
[tex]\begin{gathered} \mleft(0,2,0\mright)\Rightarrow2\cdot0+2(-2)-0=-4 \\ -4=-4 \end{gathered}[/tex][tex]\begin{gathered} \mleft(-2,0,0\mright)\Rightarrow2\cdot(-2)+2\cdot0-0=-4 \\ -4=-4 \end{gathered}[/tex][tex]\begin{gathered} (0,0,4)\Rightarrow2\cdot0+2\cdot0-4=-4 \\ -4=-4 \end{gathered}[/tex]
