Given:
There are given two right-angle triangles.
Explanation:
According to the question:
We need to find the value of x:
So,
First, we will find the value for the second triangle by using 60 degrees.
So,
[tex]\begin{gathered} sin60=\frac{y}{12\sqrt{6}} \\ \frac{\sqrt{3}}{2}=\frac{y}{12\sqrt{6}} \\ 2y=12\sqrt{18} \\ y=6\sqrt{18} \end{gathered}[/tex]
Now,
For the x:
[tex][/tex]
