A 3.50-kg bucket of water is tied to a rope and lifted vertically upward at a constant speed of 1.87 m/s for a displacement of 28.4 m. Determine the work done upon the bucket.

Respuesta :

Given:

The mass of the bucket is m = 35 kg

The bucket is lifted with a constant velocity of 1.87 m/s

The displacement of the bucket is d = 28.4 m

Required: Work done upon the bucket.

Explanation:

As the velocity of the bucket is constant, its acceleration will be zero.

So, the force on the bucket will be

[tex]\begin{gathered} F=m\times a \\ =35\times0 \\ =0\text{ N} \end{gathered}[/tex]

The work done can be calculated as

[tex]\begin{gathered} W\text{ = Fd} \\ =0\times28.4\text{ } \\ =\text{ 0 J} \end{gathered}[/tex]

Final Answer: The work done upon the bucket is zero.