Consider the given quadratic equation,
[tex]y=2x^2-4x+10[/tex]Compare with the standard form,
[tex]y=ax^2+bx+c[/tex]It is obtained that,
[tex]\begin{gathered} a=2 \\ b=-4 \\ c=10 \end{gathered}[/tex]The discriminant is calculated as,
[tex]\begin{gathered} D=b^2-4ac \\ D=(-4)^2-4(2)(10) \\ D=16-80 \\ D=-64 \end{gathered}[/tex]Since the value of the discriminant is less than zero, both the solutions of the given quadratic equation are imaginary.
Therefore, there is no real solutions of the quadratic equation.
