Given
The smallest of three consecutive integers is 15 less than the sum of two larger integers.
To find the three integers.
Explanation:
It is given that,
The smallest of three consecutive integers is 15 less than the sum of two larger integers.
Let x be the smallest integer.
That implies, x, (x+1), (x+2) are the three consecutive integers.
Since the smallest of the three consecutive integers is 15 less than the sum of the two larger integers.
Then,
[tex]\begin{gathered} x=[(x+1)+(x+2)]-15 \\ x=x+x+3-15 \\ x=2x-12 \\ 2x-x=12 \\ x=12 \end{gathered}[/tex]Hence, the three integers are 12, 13, 14.
