Coach Sikyta is measuring the basketball court in the Arena, he finds that the length is (x + 7) and the width is (3x - 1). Determinethe area of the court.
[tex]\begin{gathered} \text{the area of the court is the product of the length and the width} \\ \text{Area}=(x+7)(3x-1) \\ =x(3x-1)+7(3x-1) \\ =3x^2-x+21x-7 \\ =3x^2+20x-7 \\ \\ \text{The area is then } \\ A=3x^2+20x-7 \end{gathered}[/tex]
