Respuesta :

Given the equation

[tex]2+2(3y-7)=-3(4y-1)+6y[/tex]

Open the brackets on both sides

[tex]\begin{gathered} 2+6y-14=-12y+3+6y \\ 6y-12=-6y+3 \end{gathered}[/tex]

Add 6y on both sides.

[tex]\begin{gathered} 6y-12+6y=-6y+3+6y \\ 12y-12=3 \\ 12y=15 \\ y=\frac{15}{12}=\frac{5}{4} \end{gathered}[/tex]