Answer:
25/1326
Explanation:
In a standard deck of cards, there are 52 cards divided into 4 suits.
• Hearts (Red)
,
• Diamonds(Red)
,
• Spades(Black)
,
• Clubs (Black)
There are two red jacks and two black jacks.
Therefore:
[tex]P(\text{ picking a red jack\rparen}=\frac{2}{52}[/tex]
Next, there are 26 red cards in a suit.
Since the selection is without replacement, the number of red cards has been reduced by 1. Therefore:
[tex]P\text{ \lparen then choosing a red card\rparen}=\frac{25}{51}[/tex]
Multiply the two probabilities:
[tex]\begin{gathered} P(\text{ choosing a red jack first and then a red card\rparen}=\frac{2}{52}\times\frac{25}{51} \\ =\frac{1}{26}\times\frac{25}{51} \\ =\frac{25}{1326} \end{gathered}[/tex]
The probability is 25/1326.
The third option is correct.
