Given data:
* The mass of the golf ball is m = 0.08 kg.
* The initial velocity of the golf ball is u = 8.2 m/s.
* The final velocity of the golf ball is v = 5.9 m/s.
* The time of impact is t = 0.015 s.
Solution:
According to Newton's second law, the average force on the golf ball in terms of the change in momentum with time is,
[tex]F=\frac{m(v-u)}{t}[/tex]Substituting the known values,
[tex]\begin{gathered} F=\frac{0.08(5.9-8.2)}{0.015} \\ F=\frac{-0.08\times2.3}{0.015} \\ F=12.27\text{ N} \end{gathered}[/tex]Hencem
