The functions given are:
[tex]\begin{gathered} f(x)=2x^2-3x \\ g(x)=-4x-1 \end{gathered}[/tex]
Therefore,
[tex]\begin{gathered} f(-2)=2(-2)^2-3(-2)=2(4)+6=8+6=14 \\ \therefore f(-2)=14 \\ \\ g(7)=-4(7)-1=-28-1=-29 \\ \therefore g(7)=-29 \end{gathered}[/tex]
Final answers
[tex]\begin{gathered} f(-2)=14 \\ g(7)=-29 \end{gathered}[/tex]
