the equation is:
[tex]\frac{1}{6}d+\frac{2}{3}=\frac{1}{4}(d-2)[/tex]we solve
[tex]\frac{1}{6}d+\frac{2}{3}=\frac{1}{4}d-\frac{2}{4}[/tex]simplifying 2/4
[tex]\frac{1}{6}d+\frac{2}{3}=\frac{1}{4}d-\frac{1}{2}[/tex]grouping similar terms
[tex]\frac{1}{6}d-\frac{1}{4}d=-\frac{1}{2}-\frac{2}{3}[/tex]we solve
[tex]-\frac{1}{12}d=-\frac{7}{6}[/tex][tex]\begin{gathered} d=-\frac{7}{6}\times(-12) \\ d=14 \end{gathered}[/tex]