Given:
[tex]\bar{HJ}||\bar{ED}[/tex]
Where,
[tex]m\angle ZUJ=100^0[/tex]
Therefore,
[tex]m\angle ZUH+m\angle ZUJ=180^0\text{ \lparen Sum of angles on a straight line is 180}^0)[/tex]
Hence,
[tex]\begin{gathered} m\angle ZUH+100^0=180^0 \\ m\angle ZUH=180^0-100^0=80^0 \\ \therefore m\angle ZUH=80^0 \end{gathered}[/tex]
Hence, the answer is
[tex]m\angle ZUH=80^0[/tex]
