Answer:
[tex]\begin{gathered} a)\text{ 13,983,816} \\ b)\text{ 15,180} \end{gathered}[/tex]
Explanation:
a) Here, we want to get the number of possible selections
Mathematically, that would be selecting 6 out of 49
We can calculate this using combination as follows
We have that as:
[tex]^{49}C_6\text{= }\frac{49!}{(49-6)!6!}\text{ = 13,983,816}[/tex]
b) What this means is that, winnings would only be paid to tickets with 4,5,6 in them while the other 3 numbers can be anything
What this means is that we would be selecting 3 out of 46 numbers
Mathematically, we use the combination rule again as follows:
[tex]^{46}C_3\text{ = }\frac{46!}{(46-3)!3!}\text{ = 15,180}[/tex]
