We need to find the number which is divisible by 6,9 and 18.
The least common multiple of 6,9 and 10 is
[tex]\text{ The least common mul}tiple\text{ of 6,9 and 18 is 2}\times3\times3=18[/tex]So the numbers must be multiple of 18.
[tex]18\times4=72,\text{ 18}\times5=90,\text{ and 18}\times6=108[/tex]108 is more than 107.
So the numbers are 72 and 90.
Hence the required numbers are
[tex]72,90[/tex]