Respuesta :
In the given figure :
AB is height of the flagpole : AB = 25 feet
BC is the length of shadoe : BC = 42 foot
and angle FAE is the angle that the sun hits the flagpolem : FAE = θ
Since, line AE and line BC are the staright horizontal line, so they are parallel
and the line FC act as a transversal
So, Angle ACB = Angle FAE by corresponding angle properties
Now for angle ACB : line AB is opposite to the angle and the line BC is adjacent
Apply the trignometri ratio of Opposite side to adjacent side i.e. tangent of the angle
[tex]\tan \theta=\frac{Opposite\text{ side}}{Adjacent\text{ Side}}[/tex]Substitute the value and simplify :
[tex]\begin{gathered} \tan \theta=\frac{Opposite\text{ side}}{Adjacent\text{ Side}} \\ \tan \text{ }\theta=\frac{AB}{BC} \\ \tan \theta=\frac{25}{42} \\ \tan \theta=0.5952 \\ \theta=\tan ^{-1}(0.5951) \\ \theta=30.76^o \end{gathered}[/tex]So, angle is 30. 76 degree
Angle FAE = θ = 30.76 degree
Angle FAE = 30.76 degree
The angle that the sun hits the flagpole is 30.76 degree
Answer : The angle that the sun hits the flagpole is 30.76 degree
