The given points are (1,6) and (3,5).
First, we find the slope using the formula below.
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Replacing the points, we have.
[tex]m=\frac{5-6}{3-1}=\frac{-1}{2}=-\frac{1}{2}[/tex]Now, we use the point-slope formula, the slope, and one point.
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-6=-\frac{1}{2}(x-1) \\ y-6=-\frac{1}{2}x+\frac{1}{2} \\ y=-\frac{1}{2}x+\frac{1}{2}+6 \\ y=-\frac{1}{2}x+\frac{1+12}{2} \\ y=-\frac{1}{2}x+\frac{13}{2} \end{gathered}[/tex]