The given information is:
-The bag contained 1 kernel of corn the first day.
-The bag contained 2 kernels of corn the second day.
-The bag contained 4 kernels of corn the third day.
-Each kernel of corn weighs 0.07 grams.
As can be observed, the number of kernels of corn doubles each day.
Then, we can find a formula to find the number of kernels at day d.
The formula is given by:
[tex]K(d)=a\cdot r^{d-1}[/tex]Where a is the kernel of corn on day 1, r is the rate of increase, which is 2 (it doubles) and d is the number of days.
Thus, on day 26, the values are a=1, r=2 and d=26. Replace these values and find K:
[tex]\begin{gathered} K(26)=1\cdot2^{26-1} \\ K(26)=2^{25} \\ K(26)=33,554,432\text{ kernels} \end{gathered}[/tex]Now, as each kernel of corn weighs 0.07 grams, we need to multiply the number of kernels by this weight and find the total weight of the bag:
[tex]33,554,432\times0.07g=2348810.24[/tex]On the day 26th, the bag will weigh 2348810.24 grams.
