[tex]\begin{gathered} \text{The vertex is the point of symmetry! } \\ \text{ in absolute values, the symmetry of |x-a| is in x=a, because at that point |x-a|=0} \\ so\text{ in this case, the vertex of g(x) is where |x+2|=0} \\ \text{That is, on x=-2} \\ g\mleft(-2\mright)=8 \\ \text{The vertex is then on (-2,8)} \\ \\ the\text{ axis of symmetry is at x=-2!} \end{gathered}[/tex]
