Given data:
* The amount of work done is W = 300 J.
* The time during which the work is done is t = 15 s.
Solution:
The power used in terms of the work done and time taken is,
[tex]P=\frac{W}{t}[/tex]Substituting the known values,
[tex]\begin{gathered} P=\frac{300}{15} \\ P=20\text{ watts} \end{gathered}[/tex]Thus, the power used in the given case is 20 watts.
