write a quadratic function whose graph satisfies a.o.s is x=2 and range is y is greater than or equal to -9 and explain how. please, i've been stuck for hours and i have a math test tomorrow

Respuesta :

The a.o.s of the quadratic function is:

[tex]x=2[/tex]

And the range is:

[tex]\text{Ran}_f=\lbrack-9,\infty)[/tex]

Then, the vertex of the parabola should be:

[tex]V=(2,-9)[/tex]

And it opens upwards. Then, using the vertex form of the quadratic function:

[tex]f(x)=(x-2)^2-9[/tex]