Respuesta :

Given:

[tex]f(x)=x^2+2x+x[/tex]

Simplifying it,

[tex]f(x)=x^2+3x[/tex]

Finding value of f(-3):

[tex]\begin{gathered} f(-3)=(-3)^2+3(-3) \\ =9-9 \\ =0 \end{gathered}[/tex]

Therefore, f(-3) = 0