Work (W) done by a force(F) is given by
[tex]\begin{gathered} W=\text{ F.S}\cos\theta\text{ ;}\begin{cases}S={displacement=\text{ 12m}} \\ F={force=\text{ 50N}}\end{cases} \\ \\ \therefore\text{ W= 50}\times12\times1\begin{cases}\theta={angle\text{ between F and S= 0}} \\ cos0\degree={1}\end{cases} \\ \therefore W=\text{ 600 Joule;} \end{gathered}[/tex]Final answer is 600 Joule