Hello there. To solve this question, we just need to find the value for the altitude in which the temperature outside the airplane will be -30º F.
From the equation:
[tex]T=-0.0035A+80[/tex]
And plugging in T = 30º F, we have:
[tex]-30=-0.0035A+80[/tex]
Subtract 80 on both sides of the equation
[tex]\begin{gathered} -30-80=-0.0035A+80-80 \\ -110=-0.0035A \end{gathered}[/tex]
Divide both sides of the equation by a factor of -0.0035
[tex]\begin{gathered} \frac{-0.0035A}{-0.0035}=\frac{-110}{-0.0035} \\ A=31428.57 \end{gathered}[/tex]
Rounding the answer up to the nearest foot, we have:
[tex]A=31429\text{ ft}[/tex]