For this case we can start with the first part of the inequality and we have:
[tex]16<5x+1[/tex]We can subtract 1 in both sides and then divide by 5 and we got:
[tex]\frac{15}{5}And that's equivalent to:[tex]x>3[/tex]And for the second part of the inequality we got:
[tex]3x<6-9[/tex]And dividing both sides by 3 we got:
[tex]x<-1[/tex]And then the solution for this case would be:
x>3 or x<-1
