Respuesta :

d. 9

Formula relation:

[tex]\begin{gathered} (PB)^2=PA*PC \\ 6^2=3*PC \\ 36=3*PC \\ \frac{36}{3}=PC \\ PC=12 \end{gathered}[/tex][tex]\begin{gathered} AC=PC-PA \\ AC=12-3 \\ AC=9 \end{gathered}[/tex]