Respuesta :

[tex]\begin{gathered} 4m^3+28m^2+40m=0 \\ Fator_{\text{ }}4m_{\text{ }}from_{\text{ }}4m^3+28m^2+4m\colon \\ 4m(m^2+7m+10)=0 \\ for \\ m^2+7m+10 \end{gathered}[/tex]

The factors of 10 that sum to 7 are 5 and 2, so:

[tex]\begin{gathered} m^2+7m+10=\mleft(m+2\mright)(m+5) \\ so\colon \\ 4m(m+2)(m+5)=0 \\ so\colon \\ m=-5 \\ m=-2 \\ m=0 \end{gathered}[/tex]