to find the surface of a shape we find the area of each face and sum
Finding the areas
1.
Area
[tex]\begin{gathered} A=b\times h \\ A=12\times5 \\ A=60 \end{gathered}[/tex]
Area is 60 square ft
2.
Area
[tex]\begin{gathered} A=b\times h \\ A=12\times4 \\ A=48 \end{gathered}[/tex]
Area is 48 square ft
3.
Area
[tex]\begin{gathered} A=b\times h \\ A=12\times3 \\ A=36 \end{gathered}[/tex]
Area is 36 square ft
4. Triangles are the same, then I will solve one but I will count both on the surface
Area
[tex]\begin{gathered} A=\frac{b\times h}{2} \\ \\ A=\frac{3\times4}{2} \\ \\ A=\frac{12}{2}=6 \end{gathered}[/tex]
Area is 6 square ft
Surface
we add the area of each face
[tex]\begin{gathered} S=60+48+36+6+6 \\ S=156 \end{gathered}[/tex]
total Surface is 156square ft
