To find her z-score, we will use the formula:
[tex]Z=\frac{x\text{ -}\mu}{\sigma}[/tex]where
μ is the mean and σ is the standard deviation
From the question,
μ= 45 σ=12 and x=68
substitute the values into the formula and evaluate
[tex]Z=\frac{68-45}{12}[/tex][tex]Z\approx1.92[/tex]