Given:
Speed of car is
[tex]57\text{ }\frac{km}{hr}=15.83\frac{m}{s}[/tex][tex]g\approx9.8\text{ }\frac{m}{s^2}[/tex][tex]\mu=0.8[/tex]
Required:
Breaking distance d
Explanation:
We have formula to find the breaking distance
[tex]d=\frac{v^2}{2\mu g}[/tex]
substitute the values
[tex]d=\frac{15.83^2}{2*0.8*9.8}=15.98\approx16m[/tex]
Final answer:
Breaking distance of car at speed 57 kmph with 0.8 friction is 16 m approximately.
