The largest of the three consecutive integers - 6, 7, and 8 - is 8.
In finding three consecutive integers, it will be easier to represent them with x for the smallest integer, x+1 for the second integer, and x+2 for the largest integer.
As stated in the problem, three times the greatest integer (3 *(x+2)) is equal to 6 less than (-6) 5 times the least integer (5x). The equation formed from this relationship is shown below.
3 (x+2) = 5x - 6
Solving the equation:
3x + 6 = 5x - 6
6 + 6 = 5x - 3x
12 = 2x
6 = x
The value of x, which is 6, is the lowest integer. Therefore, the three consecutive integers are 6, 7, and 8.
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