The vertical height of fall of the ball dropped by the student is 13.06 m.
The height of fall of the ball is calculated as follows;
Apply the principle of conservation of energy as show below;
P.E = K.E
mgh = ¹/₂mv²
h = v²/2g
where;
h = (16²)/(2 x 9.8)
h = 13.06 m
Thus, the vertical height of fall of the ball dropped by the student is 13.06 m.
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The complete question is below:
A student drops a heavy ball off the top a building. The ball averages 16m/s during the fall. Assume the speed changes steadily. Find the vertical height of fall of the ball.
