The molality of the solution made by dissolving 4.08 g of hexane in 89.1 g of benzene is 0.527 M
This is simply defined as the mole of solute per kilogram of solvent. It can be expressed mathematically as:
Molality = mole of solute / mass (in Kg) of solvent
Mole = mass / molar mass
Mole of hexane = 4.08 / 86
Mole of hexane = 0.047 mole
The molality of the solution can be obtained as illustrated below:
Molality = mole of solute / mass (in Kg) of solvent
Molality = 0.047 / 0.0891
Molality = 0.527 M
Learn more about Molality:
https://brainly.com/question/4251997
#SPJ1