The area of the triangle is equal to 29 / 25 square units.
What is the area of a triangle generated by three non collinear linear equations?
Herein we find the mathematic expressions of three lines that are not collinear between them.
First, we graph the lines and determine the coordinates of the vertices and the nature of the triangle according to its internal angles with the help of a graphing tool.
The coordinates of the vertices are (3, 1.4), (4, 1) and (4.8, 3), where a right triangle is shown and the line segment between (3, 1.4) and (4.8, 3) is its hypotenuse.
Second, we calculate the length of the two legs:
a = √[(4 - 3)² + (1 - 1.4)²]
a = √29 / 5
b = √[(4 - 4.8)² + (1 - 3)²]
b = 2√29 / 5
Third, we calculate the area of the triangle:
A = 0.5 · a · b
A = 0.5 · (√29 / 5) · (2√29 / 5)
A = 29 / 25
The area of the triangle is equal to 29 / 25 square units.
To learn more on areas of triangles: https://brainly.com/question/19305981
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