find the equation of the line that contains the point (-4,-4) and is perpendicular to the graph of y=-4/5x-1

Respuesta :

The equation of the line that contains the point P(−4, −4) and is perpendicular to the graph of y = − 4/5x − 1 is y+4 = 5/4(x+4)

Equation of a line in point slope form

The equation of a line in point slope form is expressed as;

y-y1 = m(x-x1)

where

m is the slope

(x1, y1) is any point on the line

Given the following

(x1, y1) = (-4, -4)

perpendicular lope = 5/4

Substitute

y-(-4) = 5/4(x-(-4))

y+4 = 5/4(x+4)

Hence the equation of the line that contains the point P(−4, −4) and is perpendicular to the graph of y = − 4/5x − 1 is y+4 = 5/4(x+4)

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