The molarity that the stock solution should have is 8.24M.
Molarity is the concentration of a substance in a solution.
By the formula as follows: C₁V₁ = C₂V₂
Where;
C₁ = initial concentration of the stock solution
C₂ = final concentration of the stock solution
V₁ = initial volume of the stock solution
V₂ = final volume of the stock solution
Putting the values in the fromula
V₁ = 25mL = 25/1000 = 0.025L
V₂ = 2L
C₁ =?
C₂ = 0.103M
C₁ = C₂V₂/V₁
C₁ = (0.103 × 2) / 0.025
C₁ = 0.206 / 0.025
C₁ = 8.24 M
Thus, the stock solution should have a molarity of 8.24M.
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The question is incomplete. Your most probably complete question is given below:
What molarity should the stock solution be if you want to dilute 25. 0 ml to 2. 00 l and have the final concentration be 0. 103 m?
