4. A square garden has a 4-ft walkway around it. The garden has a perimeter of 260 ft. What is the area of the
walkway in square feet?

Respuesta :

If the perimeter of the garden is 260 feet and the width of the walkway is 4 feet then the area of the walkway is 1104 [tex]feet^{2}[/tex].

Given that the perimeter of the garden is 260 feet and the width of the walkway is 1104 [tex]feet^{2}[/tex].

We are required to find the area of the walkway in square feet.

Area of the square is basically the product of the side and side of the square.

Area=Side*Side

Perimeter is basically the sum of length of all the sides of the square.

Perimeter=4*Side

Finding the side of the square.

Side of the square be x.

4x=260

x=260/4

x=65 feet

Area of the walkway will be =Area of the four rectangles just formed with the sides of the square ( shown in red colour)+ Area of the four squares

left (shown in blue colour)

Area of rectangle is basically the product of its length and breadth.

Area=4(65*4)+4(4*4)

=4*260+4*16

=1040+64

=1104 [tex]feet^{2}[/tex]

Hence if the perimeter of the garden is 260 feet and the width of the walkway is 4 feet then the area of the walkway is 1104 [tex]feet^{2}[/tex].

Learn more about area at https://brainly.com/question/25292087

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