If a person walks first 70 m in the direction 37° north of east, and then walks 82 m in the
direction 20° south of east, and finally walks 28 m in the direction 30° west of north.(2pt)

a) How far and at what angle is the Aster's final position from her initial position?

b) In what direction would she has to head to return to her initial position

Respuesta :

The Aster's final position from her initial position is determined as 45.3 m.

The direction that she has to head to return to her initial position is 30° west of north.

Distance of the person from her initial position

The distance traveled by the person can be determined by making a sketch of the person's journey.

From the initial distance traveled and the second distance distance the angle between the two position is calculated as;

θ = 37⁰ + 20⁰ = 57⁰

Distance opposite to the angle

The distance opposite to the angle is resultant displacement and it is calculated as follows;

r² = (70²) + (82²)  - (2 x 70 x 82) x cos(57)

r² = 5,371.54

r = √5,371.54

r = 73.3 m

Haven walked 28 m in the same direction to her initial position, the remaining distance is calculated as follows;

d = 73. 3 m  - 28 m

d = 45.3 m

Thus, the Aster's final position from her initial position is determined as 45.3 m.

The direction that she has to head to return to her initial position is 30° west of north.

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Answer:

See below

Explanation:

I will break the legs into vertical and horizontal components then add them

Horizontal = 70 cos 37  + 82 cos 340  + 28 cos 120 =  118.96 m

Vertical  =   70 sin 37     + 82 sin 340   + 28 sin 120 =  38.33 m

Resultant distance from origin is found via pythag theorem

   d^2 = 118.96^2  + 38.33^2        d = 124.98 m

   direction FROM origin is   arctan ( 38.33/118.96) = 17.86°

       to get BACK to the origin , will have to walk 180 degrees from this = 197.86°