Step-by-step explanation:
This is trigonometry. Focusing on Y initially, we can see that Y is the opposite, and 32 is the hypotenuse. Therefore, we must use sin:
[tex] \sin(60) = \frac{y}{32} [/tex]
[tex]y = \sin(60) \times 32[/tex]
[tex]y \approx28[/tex]
Next X. We can see that X is the adjacent, and 32 is the hypotenuse, so we must use cos:
[tex] \cos(60) = \frac{x}{32} [/tex]
[tex]x = \cos(60) \times 32[/tex]
[tex]x = 16[/tex]
Now let's look at A. We can see that a is the adjacent, and 12 is the opposite, so we must use tan:
[tex] \tan(60) = \frac{12}{a} [/tex]
[tex]a = \frac{12}{ \tan(60) } [/tex]
[tex]a \approx7[/tex]
Now, B. We can see that B is the hypotenuse, and 12 is the opposite, so we must use sin:
[tex] \sin(60) = \frac{12}{b} [/tex]
[tex]b = \frac{12}{ \sin(60) } [/tex]
[tex]b \approx14[/tex]
