Write the empirical formula for at least four ionic compounds that could be formed from the following ions:

Answer:
Fe(C₂H₃O₂)₃, Fe(CN)₃, Pb(C₂H₃O₂)₄, Pb(CN)₄
Explanation:
Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.
1.) Fe(C₂H₃O₂)₃
-----> Fe³⁺ and C₂H₃O₂⁻
-----> +3 + (-1) + (-1) + (-1) = 0
2.) Fe(CN)₃
-----> Fe³⁺ and CN⁻
-----> +3 + (-1) + (-1) + (-1) = 0
3.) Pb(C₂H₃O₂)₄
-----> Pb⁴⁺ and C₂H₃O₂⁻
-----> +4 + (-1) + (-1) + (-1) + (-1) = 0
4.) Pb(CN)₄
-----> Pb⁴⁺ and CN⁻
-----> +4 + (-1) + (-1) + (-1) + (-1) = 0