molly667 molly667
  • 29-07-2022
  • Mathematics
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Please help!!!!!!!!!!!!!!!!

Please help class=

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Medunno13
Medunno13 Medunno13
  • 01-08-2022

Answer: Option (3)

Step-by-step explanation:

[tex]\frac{1}{6a^2}-\frac{5b}{3a^3}+\frac{b^2}{4a}\\\\=\frac{2a}{12a^3}-\frac{20b}{12a^3}+\frac{3a^2 b^2}{12a^3}\\\\=\frac{3a^2 +b2 +2a-20b}{12a^3}[/tex]

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