25. A chocolate bar which weighs of a pound is 9/16 cut into seven equal parts. How much do three parts weigh? (A) pound 21/112 (B) pound/27/112 (C) pound 16/63 (D) pound 47/63

For Multiplication - First, you should multiply both numerators after that you should multiply both denominators. Finally, you can simplify if it is necessary.

For Division- First, you should repeat the numerator and after that you should multiply the numerator by the reciprocal of denominators. Finally, you can simplify if it is necessary.

The question gives:

Therefore, each part will be [tex]\frac{\frac{9}{16} }{7} =\frac{9}{16} *\frac{1}{7} =\frac{9}{112}[/tex].

For knowing the three parts weigh, you should mulitiply the previous value for 3. Thus,

[tex]\frac{9}{112}*3=\frac{27}{112}[/tex].

The weight of the chocolate bar is given as:

Weight = 9/16

When it is cut into 7 equal parts, the weight of each part is

Each = Weight/7

This gives

Each = 9/16 * 1/7

Evaluate the product

Each = 9/112

The weight of three parts is then calculated as:

Three parts = Each * 3

This gives

Three parts = 9/112 * 3

Evaluate the product

Three parts = 27/112

Hence, the weight of three parts is 27/112 pounds

25. A chocolate bar which weighs of a pound is 9/16 cut into seven equal parts. How much do three parts weigh? (A) pound 21/112 (B) pound/27/112 (C) pound 16/63 (D) pound 47/63​