rogirl268
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Ariana was looking at rent costs for 555 apartments. Each rent was a different amount between \$1{,}000$1,000dollar sign, 1, comma, 000 and \$1{,}400$1,400dollar sign, 1, comma, 400 per month, except for one apartment whose rent was \$4{,}800$4,800dollar sign, 4, comma, 800 per month. [Show data]
Ariana looked at the mean and median of the rents. Then, she decided to remove the \$4{,}800$4,800dollar sign, 4, comma, 800 rent from the set and recalculate the mean and median.
How will removing this rent affect the mean and median?

Respuesta :

ogorwyne

The way that this action is going to affect the mean and the mean and the median value would be decreased than what it was supposed to be.

What is the mean?

In a frequency distribution, the mean is the number that is used to represent the average of a group of data. To get the mean, you have to add up the numbers in the data set and divide by the total number in the data set.

The formula is fx/n

When the average of $4800 is removed from the data set, the mean is going to decrease by the number and the value of fx would also decrease. Hence we can conclude that it would cause the value to reduce.

The median is the middle value, it would also cause the median in the data set to be smaller than it was.

Read more on mean and median here:

https://brainly.com/question/6281520

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