Respuesta :
The angular momentum of the moon around the earth is 2.92 * [tex]10^{34}[/tex] kg [tex]m^{2}[/tex]/s
Angular momentum a vector quantity that is a measure of the rotational momentum of a rotating body or system, that is equal in classical physics to the product of the angular velocity of the body or system and its moment of inertia with respect to the rotation axis, and that is directed along the rotation axis.
m (mass of moon ) = 7.4 * [tex]10^{22}[/tex] kg
orbit = 3.8 * [tex]10^{8}[/tex] m
L = I ω
= m [tex]r^{2}[/tex]ω
= 7.4 * [tex]10^{22}[/tex] * [tex](3.8 *10^{8} )^{2}[/tex] * (2π / 27 * 24 * 3600)
= 2.92 * [tex]10^{34}[/tex] kg [tex]m^{2}[/tex]/s
To learn more about angular momentum here
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