Respuesta :
The molecular formula of the given compound is H₂CO₃ or Carbonic acid.
Given that,
H= 3.3%
C=19.3%
O= 77.4%
No.of moles of H= 3.3/1= 3.3
No. of moles of C= 19.3/12= 1.60
No.of moles of O= 77.4/16= 4.83
Therefore,the ratio of the atoms of C,H and O= 3.3 : 1.60 : 4.83
Divide by smallest value which you get= 3.3/1.60 : 1.60/1.60 : 4.83/1.60 =2 : 1 : 3
So,the empirical formula is H₂CO₃
Let the Molecular formula is (H₂CO₃)n
Then, molar mass = (2×1+1×12+3X16)n = 62n
As the question, 62n = 60
or, n= 0.96 (round figure is 1)
So, the molecular formula is (H₂CO₃)1= H₂CO₃ i.e., the compound is Carbonic acid.
Learn more about the Molecular formula with the help of the given link:
https://brainly.com/question/13058832
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