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2. Two charges 160μC and -250μC are placed together at a distance of 150 centimeter apart. Find the force of attraction between each other. Also explain the nature of the force [Repulsing force = +ve, Attraction force = -ve]



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Respuesta :

The answer is -0.016 N, and as it negative, the nature of the force is attractive.

Finding the force of attraction

Coulomb's Law is given by :

[tex]\boxed {F = \frac{kq_{1}q_{2}}{r^{2}}}[/tex]

Solving

  • F = 9 × 10⁹ × 160 × 10⁻⁶ × -250 × 10⁻⁶ / (150 × 10⁻³)²
  • F = -360000 × 10⁻³ / 22500 × 10⁻⁶
  • F = -16 × 10⁻³
  • F = -0.016 N

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